Instant · Precise · Universal
34 units available
6 categories total
To convert deuteron masses to kg: multiply by 3.3435837724 × 10⁻²⁷.
md < mp + mn by 2.224 MeV/c² (the binding energy). This 'mass defect' represents nuclear binding energy.
For example, 1 Deuteron Mass (md) = 3.409507e-28 Kilogram-force second²/meter (kgf·s²/m).
| Deuteron Mass (md) | Kilogram-force second²/meter (kgf·s²/m) |
|---|---|
| 0.1 | 3.409507e-29 |
| 0.5 | 1.704753e-28 |
| 1 | 3.409507e-28 |
| 2 | 6.819013e-28 |
| 5 | 1.704753e-27 |
| 10 | 3.409507e-27 |
| 25 | 8.523766e-27 |
| 50 | 1.704753e-26 |
| 100 | 3.409507e-26 |
| 500 | 1.704753e-25 |
| 1000 | 3.409507e-25 |
The deuteron mass is the mass of a deuterium nucleus (one proton + one neutron), approximately 3.344 × 10⁻²⁷ kilograms.
md < mp + mn by 2.224 MeV/c² (the binding energy). This 'mass defect' represents nuclear binding energy.
To convert deuteron masses to kg: multiply by 3.3435837724 × 10⁻²⁷.
Fusion energy research (deuterium-tritium and deuterium-deuterium reactions), NMR/MRI, and neutron production targets.
The deuteron's binding energy (2.224 MeV) is quite small, making it the most weakly bound stable nucleus.
Assuming md = mp + mn exactly — the mass defect (binding energy) makes the deuteron slightly lighter than the sum.
The deuteron is the simplest nucleus with more than one nucleon. Its binding energy (2.224 MeV) is E=mc² in action.
The kilogram-force second squared per meter is an engineering unit of mass in the gravitational metric system, equal to about 9.807 kg.
1 kgf·s²/m = 9.80665 kg (exactly), based on standard gravity g₀ = 9.80665 m/s².
To convert to kilograms: multiply by 9.80665.
Historical engineering calculations where force was in kgf and F=ma needed consistent units.
This unit is the metric equivalent of the slug (imperial system). Just as 1 lb-force accelerates 1 slug at 1 ft/s², 1 kgf accelerates this unit at 1 m/s².
Mixing up mass (kg) and weight (kgf) in the gravitational system. SI removed this confusion by using newtons for force.
This unit exists because the gravitational system used kgf (force) as base, so a derived mass unit was needed for F=ma to work.



© 2026 UntangleTools. All Rights Reserved.